Recent content by CaptainMarvel

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    Max wavelength of CMB radiation

    I purposely indicated that mine was a rough calculation only. I agree that for the exact wavelength then Wien's law is the correct one to use.
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    Max wavelength of CMB radiation

    If we use the rough energy/temperature relationship: E \approx k_B T And we know the energy of a photon is related to wavelength as so: E=\frac{h c} {\lambda} Then combining these two formula we get: \lambda \approx \frac{h c} {k_B T} Plugging in for T=2.7K That gives us \lambda \approx...
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    Calculating Critical Density Using FRW and Its Implications

    Using the FRW: \left( \frac {\dot{a}} {a} \right)^2 = \frac {8 \pi G \rho} {3} - \frac {k c^2} {a^2} We define critical density by setting k = 0 and rearranging to get: \rho_c = \frac {3 H^2} {8 \pi G} Where: H = \left( \frac {\dot{a}} {a} \right) My question is does \rho include the...
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    Stargazing Telescope Illumination: Mirror Diameter & Focal Length

    Hi there, Could somebody explain how illumination - by which I mean flux per unit area - depends on the mirror diameter of a telescope and/or its focal length? Is this different for point objects like stars and for extended objects like nebulae? Thanks in advance, Nick :-)
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    Sound: Speakers Woofers vs. Tweeters

    Firstly, lower notes have lower, not higher, frequencies. Looking at the equation: wavespeed = frequency * wavelength Since all sound waves travel approximately at the same speed (340 metres per second) this means that low notes must have long wavelengths. In Summary: LOW NOTES = LOW...
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    Potential for Electric Charge over Spherical Shell using Legendre Functions

    I don't know if it's just my browser but there's a bit of my previous post that is doesn't seem to be able to process correctly. Here are those two lines again: Now we integrate theta from 0 to pi as mentioned before: V = \frac {2 \pi} {4 \pi \epsilon_o} \sum_{l=0}^{\infty} r^l R^{1-l}...
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    Potential for Electric Charge over Spherical Shell using Legendre Functions

    Homework Statement Electric Charge is distributed over a thin spherical shell with a density which varies in proportion to the value of a single function P_l(cos \theta) at any point on the shell. Show, by using the expansions (2.26) and (2.27) and the orthongonality relations for the...
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    What is the safe heel size for a 60kg woman on a vinyl kitchen floor?

    Can you show some attempt at an answer and then we can give you some help.
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    Spherical Cavity in Dielectric Subject to Uniform Field

    Please can somebody give me some idea as to where I'm going wrong? :-(
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    Spherical Cavity in Dielectric Subject to Uniform Field

    When I say 'my equation for field inside' I mean: E = \frac {3 \epsilon_r E_o} {1 + 2 \epsilon_r} as verified in the question. Thanks everyone.
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    Uniform charge across a rod, Professor couldn't answer

    Hi! What you've done looks pretty good, but after subbing in the limits from the integral on this line: \frac { \lambda } { 4 \pi \epsilon_o} ( ln (x_o + L/2) - ln (x_o - L/2) ) instead of combining the logs (using ln(A) - ln (B) = ln (A/B) ) like you've done on the next line, why...
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    Spherical Cavity in Dielectric Subject to Uniform Field

    Homework Statement The polarization charge on the surface of a spherical cavity is - \sigma_e cos(\theta) at a point whose radius vector from the centre makes an angle \theta with a given axis Oz. Prove that the field strength at the centre is \frac {\sigma_e}{3 \epsilon_o} parallel to...
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