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Following the iteration therefore for k: ##k = k##0(log(20)/log(2+φ))##+2.329621i## ##k##0## = 0 →k##1## = 0^k + c ≡c## ##c = 2.329621i## ##k##2## = c##(log(20)/log(2+φ))##+2.329621i## Which means: ##k = c##(log(20)/log(2+φ))##+2.329621i## After the conversion of the complex log into a...

Sorry, the confusion is from an error in the OP. Given the aformentioned thesis the Hausdorff dimension can be expressed in polynomial form. So, the new equation becomes: ##z=z^k+iC## where, ##k=z^k+iC## [solved numerically giving the complex number julia set] k = z(log(20)/log(2+φ))## +...

Yes, I'm aware that it's a calculable number, k = 2.3296217161703454689697018540751, but that's not the ideal format to compute ##z^k + iC##. As I'm trying to define it's first solvable iteration in quadratic form. This is a problem which was published before in a very interesting thesis, which...

Okay, so I'm working with a rather frustrating problem with a calculus equation. I'm trying to solve a calculus equation which I conceptualized from existing methods involving complex number fractal equations. I'm very familiar with pre-calculus, while being self-taught in portions of calculus...

I'm really hoping those of you here can help me solve some complex problems I've been working with lately, because the level of mathematics is a bit complex for me. I've read numerous threads here on related topics for solving related calculus equations, so I've decided to throw my hat into the...