I used the voltage of the power supply and resistance to solve for the current in the larger circuit (20V/5ohms=4 amps). I am not sure if the equation listed above is the correct one I should be using, but I tried it using the following numbers. For omega, I used 2*pi*frequency. N should...
I am thinking it may just be a flawed problem like you said. And maybe I should just go with C being the top fluid in the second beaker since although either fluid being the top has a mathematical issue, the one with B being the top fluid might be easier to spot without actually doing the math...
So are you saying that the buoyant force liquid A in the first beaker is pointing downward? in which case the density of the ball for the first beaker would come out to ρball=1/3ρB- (2/3)ρA ?
Is the answer in the back 5.85 or 5.805? I think this is just a constant velocity problem using the speed of sound. The sound is not changing its velocity so there isn't an initial and final velocity (or the initial and the final is the same if you want to use that equation). Just one...
a) I think in the beaker with A and B, A must be the top fluid and B must be the bottom. The ball sinks through the top layer but not through the bottom. In the second beaker (B and C), it does not sink through either layer. Therefore, both B and C are more dense than the ball. So B must be...