Recent content by burnst14

Okay so, heeding your advice, I solved part (a). I got a potential difference of +70 V from point c to point d. Now, closing the switch, what happens? I still can't picture it.

Homework Statement The switch is initially open and the capacitors are uncharged. The applied potential difference Vab = +210V. a.) What is the potential difference Vcd? b.) What is the potential difference across each capacitor when the switch is closed? c.) How much charge flowed through the...

So my answer is correct then? Or is my formula missing a piece? Thanks!

Homework Statement The vertical exercise wheel in a mouse cage is initially at rest, but can turn without friction around a horizontal axis through the center of the wheel. The wheel has a moment of inertia I=0.0004kg m2 and radius R = 0.06m An extremely smart pet mouse of mass m = 0.03 kg runs...

Okay going off of this, I'll go with: v0=-30/5+4.9(5) = 18.5 m/s I'm not quite sure why this works though. The unit analysis works out though... I'm a conceptual thinker, so substituting the equations likely threw me off. So is that correct?

Actually I'm just going to start over. That equation is too far in for me to remember the context.

Oh! DUH?!? Dang. Got it. Thanks guys or girls. So since v0 is equal to the velocity on the other downward side of the fall at the zero point: v0=30/5+4.9(5)

But that doesn't help because the arc portion velocities aren't in the same direction.

X = 30+2y Assuming each side of the aec is equal to distance y. Correct?

If an egg is thrown straight up in the air, then falls and reaches a point 30m below its starting point 5 seconds after it leaves the thrower's hand: What is the initial speed of the egg? How high does it rise above its starting point? What is the magnitude of its velocity at the highest...

"If I place my zero-level at the water, and the positive direction upwards, that mean that the cliff is at +20m. If I then want to drop something off this cliff, then it is also simply traveling -20m downwards? Is this correct?" Yes that's correct. "If I then define positive direction as...

Yes that's correct. And yes, the distance above the water is positive, but your rock is traveling toward the water. So your scale is set to count from 0 to 20 traveling upward, away from the water, while the rock is traveling downward, toward the water. So if the rock travels -3m, then it must...

My physics teacher was able to help me. I was missing the fact that the current would have to be made negative since the charger was inputting a current. Thanks though!

Question 1: This is correct in theory. IF you maintain awareness and think about your answers. In projectile motion, I usually use absolute values and just take a second to consider my answer. For instance, if the distance is -20m and I set gravity as 9.8 m/s2, I will get a nonreal answer...

Yes. And the reason that none of this matters to the math portion is that the stone is still traveling 20 meters. It's great that you want to understand the principles though. Now if only I could understand terminal voltage and DC circuits better... Of course!