Recent content by bopll

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    How High Should Water Be in a Half-Cylinder Tank to Be Half Full?

    nevermind, i guess i did the calculations wrong. Can anyone confirm this setup at least?
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    Choosing the Right u to Integration by Substitution

    right, this is definitely something that comes with experience. You'll notice patterns that will help you choose u. For this example, since you know you will get (something)x^2 when you take the derivative of (something)x^3, you know that the term with the x^3 will want to include u. You...
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    Taking the derivative of a function

    you're on the right track. This is a piecewise function, and in order for there to be a derivative at 1, the values for the derivatives AT 1 have to match from both sides... imagine a graph of the function. you have probably learned that there will not be a derivative if there is a cusp in...
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    How High Should Water Be in a Half-Cylinder Tank to Be Half Full?

    Homework Statement A water tank is in the shape of a half cylinder sitting on its side (not its top or its bottom). Let the radius be 10 ft and let the side-lenth on the floor be 30 feet. What should be the water height, measured from the floor up, so that the water tank is half full...
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    Using power to find velocity (a car meets a hill)

    i tried this also, maybe i made a calculation error...
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    Using power to find velocity (a car meets a hill)

    okay, so if i have to use kinetic energy, does that need i need to find the mass of the car (1/2mv^2)? that doesn't seem right...
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    Using power to find velocity (a car meets a hill)

    Homework Statement A car encounters an inclined plane Given- Weight of car in N (6500), velocity on the flat surface (22.5 m/s), power of the engine (78000), incline of the hill (8.1 degrees) Want to find- velocity on the hill (power and restistive forces remain constant) Homework Equations...
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    How Does Friction Affect the Motion of a Mass Colliding with a Spring?

    just a bump to this thread, wanting to verify: You set the K.E. and the U(spring) equal to each other i.e. (1/2)mv^2 = (1/2)kx^2 because of the conservation of energy? and this is why you don't need the force? EDIT: my problem is on a frictionless plane.
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    Kinetic energy- pushing an object up an incline.

    How do i mark a thread as solved?
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    Kinetic energy- pushing an object up an incline.

    ugh. my calculator was in radians. *facepalm*
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    Kinetic energy- pushing an object up an incline.

    that's what i did :-\ it came out to .3979 ish and that wasn't right...
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    Kinetic energy- pushing an object up an incline.

    sorry. the distance it's pushed up the hill.
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    Kinetic energy- pushing an object up an incline.

    Homework Statement An object is given an initial velocity of 3.0 m/s up a 20 degree incline. Mass= 22.3 kg and coefficient of kinetic friction is .93.Homework Equations W = (1/2)mv1^2-1/2mv0^2 W = Fdcos(u)The Attempt at a Solution So I added the forces together, mgsin(20) + .93mgcos(20)...
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