Recent content by blair chiasson

Indeed, I do! The good news is that I scored 5/5 on that question. Thanks for all of your help with it. The good news is that my Thursday lecture next week is canceled so I get an extra period of time to work on my problem set (5 extra days!). The bad news is that this caused the prof to only be...

No, I have gotten past that. With some help from collinsmark and a classmate I got through the problem. It had been handed in already before coming here for direction, so all the points for it were already lost. The good news is that I have learned a lot about integration in the past couple of...

Correct, since energy is conserved, the motion will continue back and forth across x. (part 1) and will continue across x in the positive direction (part 2). If energy was not conserved, it would at some point in time stop, depending on the loss of energy.

Right, that's exactly what I'm trying to say, my words aren't as clear as I'd like them to be. I'm not thinking of it as a literal object rolling around in a bucket against gravity, but that the potential energy being conserved, will increase and decrease throughout the motion showing that it is...

Good, I just didn't want to come off as an arse. And spoon-fed answers do NOT help me on my exam! I have poked at this some more, and I think I have come to a good description of this motion. (Still need to compute values...) Since we can define U=0 at any place on the vertical plane for...

Also, I am not trying to be rude with what I wrote above, I honestly do not make the connection between my question and your response :/ Looking back it seems rude to me, but I never meant it like that. I am exhausted and pushed to my limit and have no clue what to do. The more I struggle with...

I have considered this in terms of forces. I am unsure how your reply has much to do with my actual question. Your answers are: at x=0 the force acts in the negative x direction since the slope of the tangent to the curve of the function U(x) is positive. This remains the same answer for your...

Homework Statement The potential energy for a mss m = 1.0 kg moving in one dimension is given by U(x) = (2.5J) sin πx. The mass starts at x = 0 with an initial velocity v = 0.71m/s. (The plus sign means the motion is in the positive x-direction.) Describe the subsequent motion of the mass...

Hi again. I spent today going over integration with a friend of mine. My issue seems that when I was calculating the work done in the negative x direction, I considered the work a negative value. Also, I was having difficulties with choosing which x/y terms to subtract from the others. After a...

I did it all again, I got this time -96 J. I'm so certain I don't know what I am doing at this point that I can't really feel good about taking up your time. I will go see my prof tomorrow during his office hours. I've never had a single class on the topic of integration, and do not take any...

While typing my work, I found errors computing the integral. I will recompute and type it out.

That makes it much clearer why one of the components zeros out. I redid my calculations, please mind that I am new at integration and I likely did make an error along the way. My new result is 134 J. Is this what I should be looking to obtain? Thanks again for all the help :)

AHA! That explains my poor result. I will recalculate this and share my solution with you as soon as I have the kids in bed. (Learning physics is hard, but can be more difficult with kids running about!) Thanks again!

Thank you for your response! It is possible I performed a line integral in the wrong direction. I am just learning to work with integration this semester. I am happy that the basis of my answer is on the right track, I'll surely grab partial marks for it, it was said to be the tricky one on the...

Homework Statement A force F has components F sub x = axy-by^2, F sub y= -axy+bx^2 where a= 2N/m^2 & b=4N/m^2 Calculate the work done on an object of mass 4kg if it is moved on a closed path from (x,y) values of (0,1) to (4,1), to (4,3) to (0,3) and back to (0,1). all coordinates are in metres...