Recent content by binbagsss

  1. binbagsss

    I Fluid mechanics, Couette flow

    What is meant by axially sorry? thanks.
  2. binbagsss

    I Fluid mechanics, Couette flow

    what about the case of immiscible layers?
  3. binbagsss

    I Fluid mechanics, Couette flow

    thank you, what about the case of amplitude similar to the height of the channel but a large period. And what about case 2? e.g. with the case of differing densities with the heavier layer on top, wouldn't one expect some vertical movement downward to displacing the lighter under layer? thanks
  4. binbagsss

    I Fluid mechanics, Couette flow

    vertical is given since the plates are infinite length and i've specified their direction the set-up is in horizontal alignment. the distance does not vary. one would just assume a traditional couette flow if nothing else is specified? unsure on the last question re. a boundary, i said of...
  5. binbagsss

    I Fluid mechanics, Couette flow

    These are probably a stupid questions. For Couette planar flow with horizontal infinite length plates, the top one moving with a constant velocity in the horizontal direction, with a single layer, one assumes there is only velocity in the horizontal direction. 1)In the case of Couette...
  6. binbagsss

    A Complex potential/ observable

    i thought double creates a new line. anyway, it wont let me edit it now.
  7. binbagsss

    A Complex potential/ observable

    i didn't, it just created it on a new line and i didnt want that.
  8. binbagsss

    A Complex potential/ observable

    I have an observable denoted by C, related to a complex potential B by : ## C= \bar{B}B ,## where ##B## is a complex potential. I know that ## \left. C \right|_0 =C_0 ##, a known constant, where the evaluation at ##_0## denotes an equilibrium \ reference state. From this, I can not make any...
  9. binbagsss

    I How does a free surface flow cause non-linearity?

    in terms of the equations sorry, not physically, thanks
  10. binbagsss

    I How does a free surface flow cause non-linearity?

    How does a free surface flow cause non-linearity , is it through the boundary conditions ? Which one and how ? Thanks
  11. binbagsss

    A Tensor/Vector decomposition/representation & DOF arguement

    apologies yes I should have added that.
  12. binbagsss

    A Tensor/Vector decomposition/representation & DOF arguement

    In fluid mechanics, it is sometimes useful to present the velocity, ##U## in terms of a scalar potential ##\Phi## as:##\vec{U}=\nabla \phi## ##U## has 3 dof. ##\phi## has 1.If asked why this works, in terms of a dof argument, why is this?e.g . compared to GR common decomposition of the Riemann...
  13. binbagsss

    A Hodge operator on 4th rank tensor

    Yeh, apologies was just trying to edit the format now- need to familiarise myself with the phantom command for index spacing (just need some chicken first, too much running). I don't have a background in differential forms, but I think a tensor can only be written as a p-form if it is...
  14. binbagsss

    A Hodge operator on 4th rank tensor

    I am reading a article that defines a L, R acting Hodge dual denoted by * as: $$R^{*\alpha \mu \kappa \rho}=\epsilon^{\alpha \mu \nu \lambda}R_{\nu \lambda \kappa \rho},$$ contracting over the first two indices (and similar definition for #*^R^{\alpha \mu \kappa \rho} # contracting over the...
  15. binbagsss

    I First algebraic Bianchi identity of Riemann tensor (cyclic relation)

    which uses the definition of the Riemann tensor. my question was answered, as I said.
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