Recent content by beefcake466

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    Toy Airplane Flying: Lift Force vs. Reaction Force

    Hi I've got a question concerning a previous question I've done. A person is holding a toy airplane which flys in the air with a constant radius. is the lift force the same as reaction force? is it equal to the vertical component of the centripetal force and weight force of the airplane?
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    With static equillibrium TEE exam in a few days

    so 2.25T = (54x2.5cos32)+(200x5cos32) T= 422.70 N (2dp) so for moments questions when they are angular i need to find the length of the postion vector perpendicular to the force?
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    With static equillibrium TEE exam in a few days

    i think i know what you mean, the length is cos32 = x/5 x = 5cos32 = 4.24 (2dp) and the direction is just 32 deg isn't it?
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    With static equillibrium TEE exam in a few days

    we already know the length of the arm (5m). Yeah the weights represent forces vertically down one at the end of the arm (the mass) and the other half way through the arm (weight of the arm). but i still down understand how to work out the weather its cos or sin
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    With static equillibrium TEE exam in a few days

    can someone please show me how to determine if i use sin or cos of the angle 32?
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    With static equillibrium TEE exam in a few days

    the only bit i have trouble with is determining if i use sin or cos of the angle
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    With static equillibrium TEE exam in a few days

    sure ok what i would do is take moments of point B sum (ACW) = sum (CW) ill just say let z be the cos or sin I am not sure of how to work out 2.25 T = (5x200x z 32 deg) + (2.5x54x z 32 deg)
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    With static equillibrium TEE exam in a few days

    please help with static equillibrium TEE exam in a few days hi I've got a physics question that is static equillibrium, if anyone can help me sort out the prob i would be very happy :). ok the prob i have with it is i get the cos or sin the angle wrong like i get everythign else right exept...
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