maybe you could use the propulsion pump from a jet boat. It would be gas or diesel powered. I don't think there is a DC motor out there that will do what you are talking about.
Ok, I can do that if you direct me how. The "paper clip" shape you described is the shape I was invisioning. I am a little confused about your comment. You stated that in stationary water the piston would "always" be fighting stationary water. Conversely in the tube scenario it does not fight...
I have acknowledged that the piston and the water have to accelerate in unison, and also that there would be a terminal velocity that would be slower that the terminal velocity would be in air. I have also acknowledged that the 1kg of weight circulating the water through the system would do it...
Dear No Time,
When an object descends in a cylinder filled with water, which is directly linked at top and bottom by an identical cyliner which is also filled with water, describe the chain of events that must take place for 1chunk of water measuring 1 cubic foot to move 1 linear hand!
No, of course not. What I see happening is consistant with what I have been saying all along. The piston would accelerate slowly at first (to break the inertia of the stationary water) but once it set the water into motion the piston would accelerate at a normal 9.8mpss (less losses due to...
Another way to look at this scenario would be to compare the cylinder and plumbing to a balanced see-saw. If you had two tubes standing vertical with their bottoms and tops attatched, the water in one would balance the water in the other. Moving a cubic meter of water down in one would mean...
Fair enough,
r=10
r sqrd=100
3.14*100=314 square centemeters
314/100 = 3.14 square meters
3.14 sq meters * 1 meter long =3.14 cubic meters
weight of 314 ccs water 3.14 kg (I live in the US incedentally)
Length was given, 20m
If you are interested I posted this question on yahoo answers...
Consider a 20cm diameter cylinder. 1 linear meter = 3.14 cubic m. So for the piston to descend 1 meter, 3.14 m3 of water must exit. Likewise for the piston to descend 1m in 1 sec the water would have to flow at 3.14 cubic meters per second. In a 20 cm wide pipe I really don't think the back...
I said two objects of identical size with different mass. That means the density of the two objects are different. Your foil scenario is the same as my scenario. There both right. Read and think before you make corrections. Also are you picturing a 100kg object in a piece 3/4" pipe? Pipe...
I suppose this is similar to an unbalanced wheel. Also your hollow doughnut applies, if it was oval shaped with long straight sides, so one side could be used as our cylinder. Call it what you will. Does anyone agree with me that the piston will fall "fast" and not "slow?" Can anyone prove...