Recent content by beborche

@rude man, thanks for your explanation. Also thanks for pointing me in the direction of Lenz's law. I should've revisited that one before even posting the question here.

Ok guys. Thanks for your replies. This was driving me nuts. From your answer, phyzguy, I take it there's no correct way of determining the direction of dS? Whatever floats your boat?

Homework Statement There's a magnetic field B in +\hat{z}. A rectangular loop is lying in the xy-plane. Three sides are static, the 4th one is moving with velocity v along the direction of +\hat{y}, making the rectangular larger and larger. The length of this moving side of the rectangle is L...

Homework Statement Simplify the circuit as much as possible to prepare it for node analysis. Homework Equations KCL (sum of all currents through a node equal zero) Ohm's law V=RI The Attempt at a Solution I'd like to use node analysis. But first I have simplified the circuit and...

@ehild Alright. I get it now. Tanv will produce the same result for all angles v + n*pi, where n=1, 2, 3... Thank you!

Homework Statement Write arctan8 + arctan11 as an expression containing max one term with arctan.Homework Equations tan(u+v) = \frac{tanu+tanv}{1-tanutanv} arctan(tanx) = xThe Attempt at a Solution u = arctan8, v = arctan11 tan(u+v) = \frac{tanu+tanv}{1-tanutanv} = \frac{8+11}{1-8*11} =...

Alright. Yes i meant 1/(4sqrt(3)).

@BruceW Thanks man. I knew I could just hit arcsin(1/7) in on my calculator to find the angle and then from there find the adjacent side, but we're not allowed to use the calculator. But then I realized you meant Pythagoras theorem, which I ofcourse didnt think about... Thanks again! I think...

Homework Statement Calculate tan(arcsin(1/7))Homework Equations arcsinv = x => sinx = v sinx = (opposite/hypotenuse) (in a right-angled triangle) tanx = (opposite/adjacent) The Attempt at a Solution Well I realize that arcsin(1/7) is an angle. Let's call it v. I also know that arcsin(1/7)...

Thank you, I solved it! Not by finding acceleration in the case of friction first, but thanks to you reminding me of that what I calculated was the average velocity. These two lines messed it up: v = s/t = 2.67 m/s a = (v-u)/t = 0.71 m/s² Where it says (v-u), it should say 2*v. Since v = average...

Ah you're right. I see the mistake. F = ma = mgsin\theta - ukgcos\theta Rearrange and you'll get this uk = \frac{a + gsin\theta}{gcos\theta} = \frac{0.71 + 9.8sin(35)}{9.8cos(35)} = 0.787 should be F = ma = mgsin\theta - ukmgcos\theta Rearrange and you'll get this uk = \frac{a -...

Homework Statement A pig is sliding down a ramp that has an angle of 35 degrees from the horizontal plane. If the friction coefficient was 0 the ride would only take half the time. What is the kinetic friction coefficient between pig and ramp?Homework Equations Fnet = ma v² = u² + 2as a =...

Alright, then I understand. Savvy :) And thanks for explaining.

I understand everything except where m²/s² comes from. Unless they are the units for v², i.e. velocity squared? (In that case, why no units for gravity or mass?) thanks // Beborche

Credits to you! :P 0,175m is the correct answer. I don't understand a few things just yet but I'll dive into it and see if I get grasp it. Thanks a lot! and brb