Recent content by Beanie

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    Coefficient of Kinetic Friction

    Thank you for the help! This makes a lot of sense now!
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    Coefficient of Kinetic Friction

    Right, okay. So, in the horizontal direction, the force of friction and the force of the push (150N) are both affecting the object. They are also in opposite directions. I drew a FBD for it (attached file), however I am still stuck on how you calculate the Force of Friction.
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    Coefficient of Kinetic Friction

    The normal force/force of gravity?
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    Coefficient of Kinetic Friction

    Homework Statement A horizontal force of 150 N is used to push a 50.0 kg packing crate a distance of 5.00 m on a rough horizontal surface. The acceleration of gravity is 9.81 m/s2 . If the crate moves with constant velocity, calculate: a) the work done by the force. Answer in units of J. b)...
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    Newtons Laws car deacceleration

    Okay, this makes more sense. So... Ff=mus*Fn Ff=0.218*18620 Ff=4059.16 And then because sum of all forces is the force of friction, 4059.16=(1900)a a=2.1364m/s^2
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    Newtons Laws car deacceleration

    Homework Statement A 1900 kg car moves along a horizontal road at speed v0 = 23.6 m/s. The road is wet, so the static friction coefficient between the tires and the road is only μs = 0.218 and the kinetic friction coefficient is even lower, μk = 0.1526. The acceleration of gravity is 9.8 m/s2...
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    Calculating Time for Ball to Reach Fence Plane

    Homework Statement Determine the time it takes for the ball tor each the plane of the fence. Answer in units of s. (VIEW IMAGE ATTACHED) Homework Equations Vf+vi+at d=vit+.5at^2 vf^2=vi^2+2ad The Attempt at a Solution [/B] I found Vix to be 11.59 using trig. I then used the second equation...
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    How Does Projectile Motion Affect Speed and Angle on Impact?

    Homework Statement A particle travels between two parallel ver- tical walls separated by 25 m. It moves to- ward the opposing wall at a constant rate of 9.2 m/s. It hits the opposite wall at the same height. The acceleration of gravity is 9.8 m/s2 . (IMAGE FOR CLARIFICATION ATTACHED) a)...
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    Projectile Trajectory Homework: Finding Time of Flight Without Air Resistance

    Oh right, okay so my time is half of the time that it takes the shell to fly. So I must double my time?
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    Projectile Trajectory Homework: Finding Time of Flight Without Air Resistance

    Yes, I used the y component of the vector as explained in my reply to "SteamKing" However, I still got the answer wrong. Any ideas on where I went wrong?
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    Projectile Trajectory Homework: Finding Time of Flight Without Air Resistance

    Thank you! So I understand what the projectile looks like. I have drawn a picture and tried a different attempt to what I was doing before. I found the x and y components of the angle. I then used the y component of this answer as the initial vertical velocity, used 0 as the final vertical...
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    Projectile Trajectory Homework: Finding Time of Flight Without Air Resistance

    I understand this, however how can you calculate final velocity with just the angle and initial velocity?
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    Projectile Trajectory Homework: Finding Time of Flight Without Air Resistance

    Homework Statement An artillery shell is fired at an angle of 23.9◦ above the horizontal ground with an initial speed of 1530 m/s. The acceleration of gravity is 9.8 m/s2 . Find the total time of flight of the shell, neglecting air resistance. Answer in units of min. Homework Equations...
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    Expressing Vector R in Terms of A, B, C, & D

    There is no stated answer, however these are the possible answers (VIEW ATTACHED IMAGE)
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