A researcher surveys 25 people and finds that their average commute is 15 minutes with a standard deviation of 1.5 minutes. Calculate the 95 percent confidence interval on variance. Do most people have a commute of 20 minutes?
Confidence interval for variance? should I just use the variance...
I have data outlining the number of people who play a musical instrument
and data outlining the total number of people in each city
play an instrument....population
255......1 009 924
179......3 500 048
556...... 957 293
etc.
how do I write the proportion of people who play an...
An ice cream owner randomly samples 100 people. He finds that 50 people like ice cream and of those 50 people, 25 like chocolate ice cream. Calculate with 95% confidence that over 60% of people like his chocolate ice cream.
It just occurred to me that it was not clear that the 50 people liked...
I'm assuming it is 60% of the total population. so if that's the case your saying that I should use 25/100 rather than the 25/50? then I don't know what the sample of 50 subset of people is for ( I don't know why that is included in the question).
I don't know what to do
In a sample of 100 people. 50 people like ice cream, of those 50 people, 25 like chocolate.
Calculate with 95% confidence, that over 60% of people like his chocolate ice cream.
H_0= mu > 0.60
H_1=mu < 0.60
25/50=0.50% of people like chocolate ice cream
(0.50-0.60)/...
sorry, 5% of all students are not enrolled in sports. If there are 500 students on a bus. What is the expected numbers of students who are not enrolled in sports on any given bus?
hehehe yes I suppose it is quite a large bus!
would the solution change at all if it were worded as "5% of students all students are not enrolled in sports"...?
thanks
Hi, I have a quick question
5% of students on a school bus are not enrolled in sports. If there are 500 students on a bus. What is the expected numbers of students who are not enrolled in sports on any given bus?
So, 5%(500)=25??
is this correct? Thanks