if use sin to find Fa it gives me 11.025 which makes the tension equal 3.56 which is also wrong.
maybe I am not writing the equation right.
I am getting Tension to be T=ma g sin theta- fa-ma a
which I am getting 4.5(9.8)sin 30-19.096-(4.5)(9.8) which = 13.99
am I setting the equation...
Block A in the figure below has mass mA = 4.5 kg and is sliding down the ramp. Block B has mass mB = 2.2 kg. The coefficient of kinetic friction between block B and the horizontal plane is 0.50. The inclined plane is frictionless and at angle 30°.
part a is to find the tension
the equation...
For some reason I am struggling with these problems. I am lost as a goose trying to fly south for the winter!
Homework Statement
9^(5-x2)
and
another derivative problem using chain rule
r/square root of the whole term r^2+5
Homework Equations
1st equation= d/dx= a^x ln a
2nd...
oh i see what I did wrong! apparently the homework program did not like that I did not put a space between [-csc^2 and cos theta) wow here I was thinking I did not know what I was doing and it was just an input error, not a mathematical error! Got to love technology sometimes!
yes, the question you have is right.
I worked the problem by looking at an example video that comes with our online book.
the instructor in the video further broke down from the answer in the sample problem, which was cot^2(sin theta), which the answer is -2cos theta * cot(sin theta) *csc^2...
I think there is one more step that I am lost on. I ended up getting 2 cos theta *cot(cos theta) *csc^2(-sin theta), which webassign did not like :( ahhhh
Homework Statement
cot^2(Cos\theta)Homework Equations
chain rule
f prime (x) = f prime(g(x) * g prime (x)
The Attempt at a Solution
I am not sure if I am just inputting the wrong numbers into webassign or I am just missing and important trig derivative and just completely off of the boat...