Thanks hilbert2,
I see what you are saying. I also just found another way to do it, ill post it:
Multiplying the expression by (sqrt(x^2+1) + x)/(sqrt(x^2+1)+x) you get lim(1/(sqrt(x^2+1)+x) = 0.
I see that you have used the sandwich theorem, and i suppose that is an easier way to do it. I am...
Hey guys, I have been trying this question for 40 minutes and I can't get the answer.
Evaluate lim as x approaches positive infinity(sqrt(x^2+1)-x).
I tried the La-Hopital's rule, but even then I still get inf/inf. I know there is an algebraic manipulation I need to make, but I keep getting...
But my function read_one_vote changes the contents of the array one_vote_array everytime it is called, so shouldn't that array be different for each node?
I have pasted my code here : http://pastebin.com/nMNarH9i
It is in language C.
Basically, I am reading in 5 numbers at a time.
Putting these numbers in array one_vote_array.
Then I need to put this array in a structure vote_node.
I also then change my next pointer in the structure to head...
1. Give information
Let T: P3 ---> P3 be the linear transformation described by:
T(p(x))=p(x+1)+p(2-x).
Find the matrix of T with respect to the standard basis b {1,x,x^2,x^3}.
The Attempt at a Solution
I found the transformations on the standard basis b:
T(1) = 2
T(x) = 3
T(x^2) =...
OH my fault, I see they are linearly independent. So could I generalize this and write span(S) = {a(1,1,2) + b(1,-1,2) + c(0,0,0) + d(0,2,4) + e(-1,3,6)} given a>0, b<0, c,d and e are any real numbers?
So for any values of x I pick. the x vectors will be linearly dependent and they cannot form my span? So would that mean the span(S) = span of linearly independent independent vectors in S. So span(S) = <a(0,2,4)+b(-1,3,6)>?
Homework Statement
Give S = {(x,|x|,2|x|) | x \in R} \bigcup {(0,2,4),(-1,3,6)}, find span(S)
Homework Equations
I know that span of a finite set of vectors is given by <a(0,2,4) + b(-1,3,6)+c(x,|x|,2|x|)>, where a,b,c are any real numbers. Can i use that same way to find the span of this...