V^2/R, correct? Then, since I know voltage is the same, I would be able to determine resistance values from there.
However, is there a way to prove this not algebraically and more conceptually?
So, if I were to plug numbers in given that the voltage drop was the same, I see that the 100 W has a lower amount of resistance, but why is this so? I thought that if a bulb has higher resistance, there would be a greater power value?
Homework Statement
If you have a 100 W bulb and a 60 W bulb connected to separate electrical outlets, which will be brighter? Which has more resistance? Explain.
2. Necessary formulas
P=IV and (maybe?) I=V/R
3. The Attempt at a Solution
I know for sure the 100 W bulb is brighter. However...