Recent content by AutGuy98

Hi Klaas van Aarsen, I completely understand where you're coming from with what you said in your previous post and I can see why you would say that. I'll start by saying that while I have posted a lot with little to no work being shown on my own end, the truth is that I just don't understand...

Hey guys, I just wanted to say that I hope my two posts regarding these exercise set questions will not be forgotten and go unanswered. I pray that this is not the case here and if it is not, I also wanted to say that it would really mean the world to me if someone out there could please...

Hi HallsofIvy, Thank you for responding to my post in such a timely manner. Yes, I do believe the information you have stated is correct. However, seeing as I have no clue where to go or what to do (much less, how to do anything) with these problems, would you and whoever else decides to help...

Hey guys, Got what seems like a simple problem at first, but has been giving me difficulty in trying to prove. Please help me with it and show me what to do because I have no clue really. Here is what it asks: Prove that if A is a countable set and the function f:A\impliesB is onto, then B is...

Hey guys, I have some more problems that I need help with figuring out what to do. The second (and final) one is divided into 4 mini-problems, sub-sections, whatever you would like to call them. It asks: (a) Show that the set of automorphisms of a group G, denoted by Aut(G), is a group under...

Hey guys, I have some more problems that I need help with figuring out what to do. The first one is divided into 4 mini-problems, sub-sections, whatever you would like to call them. It asks: (a) Show that (Z/4Z,+) is not isomorphic to ((Z/2Z) x (Z/2Z),+). Find a homomorphism from (Z/4Z,+) to...

Hey guys, got another question for you to look at and hopefully help me out on. For each of the following functions, prove that f is one to one on E and find a formula for the inverse function f-1. (a) f(x)=x2+3x-6 and E=[-3/2,infinity). (b) f(x)=((x)/(x2+1)) and E=[-1,1]. Please help me...

Thank you Euge for all the help. But, if you would be so kind as to provide the information, how exactly do you find the index values for each choice of H from here? Thank you again.

Hi Euge, The same situation applies here as was the case with 2(b) and 2(c). I only have a small amount of understanding when it comes to what is going on in my Elem. Abstract class, so if you would be so kind as to please just provide me with the solution whenever you are able, as I am still...

Hi Euge, The same situation applies here as was the case with 2(b). I only have a small amount of understanding when it comes to what is going on in my Elem. Abstract class, so if you would be so kind as to please just provide me with the steps to the solution whenever you are able, as I am...

So would the generators of C12 then be (e1,e2,e3,...,e12)? I am unsure of how exactly to finish this off. Could you please either give me another hint or solve it for me, because I am limited on time and honestly have only a minute sense of what is going on in my Elementary Abstract Algebra...

In the book, it says, "You may have noticed that the order of a subgroup H of a finite group G seems always to be a divisor of the order of G. This is the theorem of Lagrange." Please let me know if this helps or not. Also, thank you for your help on 2(b). It is very much appreciated!

Hey guys, Sorry that it's been a decent amount of time since my last posting on here. Just want to say upfront that I am extremely appreciative of all the support that you all have given me over my last three or four posts. Words cannot express it and I am more than grateful for it all. But, in...

Hey guys, Sorry that it's been a decent amount of time since my last posting on here. Just want to say upfront that I am extremely appreciative of all the support that you all have given me over my last three or four posts. Words cannot express it and I am more than grateful for it all. But, in...

Hey guys, Sorry that it's been a decent amount of time since my last posting on here. Just want to say upfront that I am extremely appreciative of all the support that you all have given me over my last three or four posts. Words cannot express it and I am more than grateful for it all. But, in...