Recent content by Attraction

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    Free radical halogenation question

    Homework Statement The initiation step in chlorination of methane is as follows... http://upload.wikimedia.org/wikipedia/en/thumb/3/32/MethaneChlorinationMechanismInitiation.svg/260px-MethaneChlorinationMechanismInitiation.svg.png We get two chlorine radicals as a result. Next we have two...
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    Quick (and maybe dumb) question on chirality

    Homework Statement How are my hands not constitutional isomers? The Attempt at a Solution I read this in a book today (Organic Chemistry for Dummies - good book actually), and I was covering chirality. Now, I am a bit shaky on it and need to go over it, but I got stuck on this for...
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    Low IQs of Scientists: Francis Crick & More

    This is the key point. Teachers tend to teach in THEIR OWN LEARNING STYLE. Some students are predominantly auditory learners, others are predominantly visual, others are predominantly physical and so on. Generally we have all three aspects but are more dominant in one. Teachers tend to only use...
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    Low IQs of Scientists: Francis Crick & More

    Agreed. No matter how high your intuitive aptitude is, if you don't put forth the necessary effort, you will not achieve as much as someone of a lower intuitive aptitude who puts in many more hours. It's all about ATTITUDE and GOALS. I've seen it and also been a victim of it. People who I...
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    First Order Reaction calculation

    YES! I have figured it out. Sometimes I wonder if I have the aptitue to learn this chemistry stuff, but I am doing well so far and I am teaching myself so it's obviously not going to be easy all the way. Anyway.. this was where I left off last time. ln[AB]t = -2.3 x 10-7 x 138 (seconds) +...
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    First Order Reaction calculation

    Homework Statement The decomposition of AB is first order with a k = 2.3 x 10-7 s-1 at 45oC. If the initial concentration is 0.25 M, the concentration after 2.3 min is: Homework Equations ln[A]t = -kt x ln[A]0 The Attempt at a Solution I have subbed in the values I have but I...
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    Electronic Structure (magnetic quantum number)

    I figured it out Fenn, thank you!
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    Electronic Structure (magnetic quantum number)

    There are 6 other electrons in the 4d orbital, which can hold 10 electrons (2 in each orbital). Would I be right in saying that each orbital has a respective value of 2/1/0/-1/-2? I think so. I know about hunds rule and the magnetic spin number so my question is, how do I know which value...
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    Electronic Structure (magnetic quantum number)

    OK, let me start again. The 44th electron is in the 4d orbital. Principle quantum number = 4. d orbital = 2, therefore the azimuthal quantum number is 2. Magnetic spin number is -1/2. Because the azimuthal number is 2, the possible numbers for the magnetic spin quantum number are...
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    Electronic Structure (magnetic quantum number)

    Homework Statement Describe a possible set of quantum numbers for the 44th electron in mercury. The Attempt at a Solution I can't help but feel a bit embarrassed by some of the questions I ask on this forum. Nevertheless, I am having problems with figuring out what the magnetic...
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    Stoichiometry again (using solutions)

    perfect, thanks man. I understand fully now.
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    Stoichiometry again (using solutions)

    I don't know how, but I copied the wrong question here in this thread. I started with grams but there is no grams in the question. The question I was supposed to copy was this one... 1. Homework Statement Given the following equation: H2SO4 + Na2CO3 ----> Na2SO4 +...
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    Stoichiometry again (using solutions)

    Homework Statement H2SO4 + Na2CO3 g Na2SO4 + H2O + CO2 Calculate the molarity of the H2SO4 solution if it takes 40.0 mL of H2SO4 to neutralize 46.7 mL of a 0.364 M Na2CO3 solution. The Attempt at a Solution The equation is balanced. My plan was...
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    Stiochiometry (with solutions)

    Hi Borek. I just figured it out. My mistake was that to convert from moles H2SO4 to concentration H2SO4 I was dividing by the total amount of solution rather than the H2SO4 in the solution. Silly stuff, I need to be thinking more clearly. Thanks for that link. It's helpful.
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