Recent content by ashleyrc

Wait, how is it possible to have a failure rate for celibacy? I believe only one woman did that, and she is heralded for it! :) I think I understand your logic for the Null Mehod, since it is incorporated in each of the percentages I originally gave in my problem. So what you are saying is...

So I went through the calculations, and my chances of getting pregnant are the following if I use: -Sprintec and the Withdrawal method, = .2% (So 1 out of every 500 women would get pregnant…) -Sprintec and the Today sponge, = .3% (1/333 women get preggo…) -Sprintec and condoms, = .14% (1/715...

Ok, so I started Sprintec birth control pills a week ago, and the chances of getting pregnant while on it alone is 1% per year of use (a little less actually, but for the sake of simplicity, we’ll stick with 1%). I also have condoms, the Today sponge, and can also use the withdrawal method...

g'(x)=2x(f(x/(x-1))+x^2(f(-1/(x-1)^2))?

wha am i using the chain rule for? the f(x/(x-1))? the product rule would be for x^2 and whatever that chain rule produces, correct? i'll try it out...

:redface:Uh oh... secret's out, yeah, i didn't realize i couldn't have multiple accounts. so "abbykeck" is technically still online...:blushing:

yeah, i have learned limits, and I'm going to guess a horizontal tangent line is located wherever the slope is 0. i have seen too many of those equations though.

Homework Statement determine where the graph of the function f(x) = (x-4)/(x^2-7) has a horizontal tangent line. Homework Equationsused quotient rule. factored and simplified The Attempt at a Solutioncame up with ((x^2-7)-(2x^2-8x))/(x^2-7)^2 then set to 0, and came up with...

yeah, i guess that makes sense. the division signs in the equation tend to confuse me. i'll have to do some more problems before i get the hang of it. it's still pretty confusing. i must've used maple wrong. I've only started using it the past week. it seems like i need a degree just to...

Homework Statement Find the derivative of: cube root of (1/(2-3x)) Homework Equations use chain rule (i think?):(f of g)'(x) = f'(g(x))*g'(x) The Attempt at a Solution first, i changed the cube root to the exponent 1/3. second, i did the derivative and came up with...

yeah, i remember the preofesor mentioning l hopitals rule, but i don't really know it yet, i'll look it up and get back w/u all later

ok, so it would = (sin x)^2/ x^2, then the limit is 1. because you can cancel the ^2 on top and bottom to = (sin x)/x, which is 1

Homework Statement limit as x approaches 0 of (sin^2 (x))/x^2 Homework Equations i generally know how to solve the equation, but I'm not sure what to do about the top. is sin^2 (x) the same as sinx^2? The Attempt at a Solution

thank's a lot! yeah, the words just made the math all the more confusing, but at least i get the concept now. thanks for all of your help!

yeah, i think so... i was incorrect in using f(a) and a interchangably, as with f(b) and b. it makes more sense the way you had it written. so my question is not actually asking me to find the exact coordinates where the zero is located, but rather to prove that the zero is located somewhere...