JBA,
Thanks for your help with this. I was able to calculate the correct answer and follow your method, with the exception of the 60 sec in the 1/qm value. When we calculate qm, we obtain a value of .0124 lbs/sec. If I multiply this by 60 sec, I get .7455. Taking the inverse of this for my...
Hi JBA,
I used 11.75 as my Qm value but did not receive the correct answer. I thought, perhaps, my units were incorrect so I converted all inch measurements to feet and all minutes to seconds. I don't see how the pounds value, from value Pe, which is either PSI or PSF cancels out. All the...
I have a follow-up question. In the delay time section, the author cites the following equation:
Td = (Pe*g*Ve*ks)/(Qm * Vs^2)
where Td = time delay (seconds)
Pe = change in pressure (79.7 - 34.91 psi)
g = .075 lb/ft^3
Ve = exhaust volume - 5.07 in^3
ks = 1.4 for air
qm = flow rate - this...
JBA,
Thanks for responding. I took your values came up with the value the author cites in the article - 1.185.
**Please note to anyone reading this threat that I made a typo in my original post - 1.833 cfm should be 1.185 cfm.**
Q = 22.48*Cv (((P1-P2)*P1)/(T*G))^1/2
9.94 = 22.48 * (Cv) *...
Hi,
I am following this particular article from machinedesign.com about properly sizing a pneumatic system - http://machinedesign.com/archive/right-sizing-pneumatic-motion-systems
In the section Valve Exhaust Port, he does a calculation for the valve loss coefficient and arrives at 1.833 cfm...
Edgepflow,
Thanks for the excellent feedback and advice! Do you have any suggestions for obtaining entry positions into the nuclear industry? Is it a growing sector and what is the best way to position myself to find employment?
I don't know much about the energy areas but it does...
Hi -
I have a question here for the board. Ten years ago I received my Bachelors degree in Industrial Manufacturing and Systems Engineering. Due to economic conditions at the time, I took a job as an analyst and before too long, realized that my career veered down the business path.
I am...