ok so what you are saying is that if i use ohms law V=I*R
I will have to use the 8 ohm resistor times by the current of 2.142= 17.136V
Is this the voltage after it went through the resistor or is this the amount of voltage drop?
Homework Statement
The circuit has a battery Voltage of 30V, a resistor of R1(8ohms), R2 (2Ohms) and R3 (4ohms) in series. Calculate the voltage drop over R1
Homework Equations
Please give me the proper equation of this? The one I've got says you take 30-8I-2I-4I=0
Wich gives you...