Recent content by arctic_viper

I see. Thanks.

What do you mean by orders of magnitude?

Ya that's pretty much what I did. I converted ml to liters by dividing by 1000. After that I multiplied the [OH-] by the L to get the moles of [OH-]

Yes, sorry, I had my exam yesterday and was really tired. But I did find the concentration by doing the following. 14-12.50 =1.50 then 10^-1.50 to get 3.16x10^-2 Then I divided that by the 50.00ml of water to find initial moles. After doing that I made an IRF table..I also found the...

So, 2NaOH(aq) + H2SO4(aq) ---> Na2SO4(aq) +2H2O(l) ?

Homework Statement A 50.0 mL aqueous solution of sodium hydroxide has a pH of 12.50. If 36.00 ml of 0.0200 mol/L sulfuric acid is added to this sodium hydroxide solution, what will be the new pH of the resulting solution? Assume that the temperature stays constant at 25C, and that the volumes...

How did you do all of it?