Ah, I see what you mean.
Now I've solved it. And as a courtesy to future answer-seekers, here's how.
Use the kinematic equation delta-x = 0.5(v0-v)t
12.0 m = 0.5*v*4.0 s
v = 6.00 m/s
then, omega = 20.0 rad/s
Plugged into the energy equation above, I = 4.09 kg*m2
Homework Statement
You are asked to measure the moment of inertia of a large wheel for rotation about an axis perpendicular to the wheel at its center. You measure the diameter of the wheel to be 0.600 m. Then you mount the wheel on frictionless bearings on a horizontal frictionless axle at...