Hi WWGD,
Thank you so much.
So I integrated the equation
∫(∂M/r∂r+∂2M/∂r2 )= ∫A ----(1)
ie ∫∂M/r∂r+∫∂2M/∂r2 = ∫A
1/r*M-∫-1/r2*M + ∂M/∂r = A*r+C1 (integral by parts)
2*M/r+∂M/∂r = A*r+C1 ----(2)
Integrating eq(2) again
∫2*M/r+∂M/∂r = ∫A*r+C1
Which gives,
2*M*ln(r)+M = A*r2+C1*r+C2...
Hi,
Could you please help me to solve a second-order differential equation given below
∂M/r∂r+∂2M/∂r2 = A
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