Got the bounds I think , thanks.
Part 4 of that q asked:
Let B be a bounded subset of R. Prove -B + S is bounded from below.
How would I know the bounds of B? Does it have no lower bound?
No I haven't done proofs
I simplified the fraction in the equation given and factorised out (x-1) then got a polynomial to degree one in top and a polynomial to degree 2 on the bottom.
If i want to show it's smaller than 1 should I rewrite 1 into a polynomial with degree 2÷polynomial to degree 2
I know that for a set to be bounded it is bounded above and below, for the bound below is it 0 and n cannot equal 1 and u paper bound is inf but how do I prove that it is bounded?
(e-√x)/√x (integral from title)
I integrated by substituting and the bounds changed with inf changing to -inf and 1 changing to -1
My final integrated answer is -2lim[e-√x]. What happens to this equation at -inf and -1? As I can't put them into the roots