Recent content by Anne5632

  1. A

    Is there a way to prove that a set is bounded using calculus techniques?

    True, To find the lower bound of -B I thought I could use that theorem
  2. A

    Is there a way to prove that a set is bounded using calculus techniques?

    No I haven't, and none of the other exercises are similar. But I'll looks throught the theorems in that topic
  3. A

    Is there a way to prove that a set is bounded using calculus techniques?

    Sorry meant to write S, A is the set S described in the question above
  4. A

    Is there a way to prove that a set is bounded using calculus techniques?

    Got the bounds I think , thanks. Part 4 of that q asked: Let B be a bounded subset of R. Prove -B + S is bounded from below. How would I know the bounds of B? Does it have no lower bound?
  5. A

    Is there a way to prove that a set is bounded using calculus techniques?

    No I haven't done proofs I simplified the fraction in the equation given and factorised out (x-1) then got a polynomial to degree one in top and a polynomial to degree 2 on the bottom. If i want to show it's smaller than 1 should I rewrite 1 into a polynomial with degree 2÷polynomial to degree 2
  6. A

    Is there a way to prove that a set is bounded using calculus techniques?

    the inf of the set is 0 so does that count in the interval?
  7. A

    Is there a way to prove that a set is bounded using calculus techniques?

    I know that for a set to be bounded it is bounded above and below, for the bound below is it 0 and n cannot equal 1 and u paper bound is inf but how do I prove that it is bounded?
  8. A

    Compute lim as n tends to infinity of f(xn)

    As n tends to inf, the fraction goes to zero so would the lim just be X?
  9. A

    Integration of (e[SUP]-√x[/SUP])/√x

    Thank you, I originally let my substitution = -√x But √x is better Final answer now is 2/e
  10. A

    Integration of (e[SUP]-√x[/SUP])/√x

    (e-√x)/√x (integral from title) I integrated by substituting and the bounds changed with inf changing to -inf and 1 changing to -1 My final integrated answer is -2lim[e-√x]. What happens to this equation at -inf and -1? As I can't put them into the roots
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