Recent content by Anhkha

Oh! Didnt see that!i Will try to see if i get something else. Thank you EDIT: Solved! Cant believe i used to hours to figure out a stupid mistake like that haha. Thank you a lot!

isnt 1.85*6 Isnt 1.85*(6/12.5)=0.888? 1.85*(0.48)=0.888?

Known h0=3.0m d1=6.0 m (From top of the hill diagonaly down to the flat area) d2= 12.5 m (Flat area) Ep=0J (Since no potenial energy at the end of the ride) Ek0=0j (Since no movement at the top of the hill) Friction on d1 is 85% of the friction power to d2 Unknown V(Velocity)

I posted some of my calculations above which might be completely wrong. However i will try to do make some more calulculatiions i can post.

Here is some of my calulations, warning: this might be completely wrong. EDIT: s=distance. S is distance in my language :)

The flat portion is 12.5m. 6.5m is from the diagonal line from the top of the hill to the flat area. Sorry for late answer, just took bus from library to home. Maybe this drawing can clear some things up.

Homework Statement "A little girl is sliding down a snowy hill on her sledge and out on a horizontall flat area. The girl has a physics interested mom which wants to know what the maxium speed the sledge can reach. She measures that the hill is 3,0m high and 6,0m long. The sledge slides for...