From Newton's second law:
$$T_{x} = F_{turn}$$
So
$$T \sin \theta = ma$$
$$T_{y} = F_{y}$$
so
$$T \cos \theta = mg$$
Equate the two equations to get:
$$ \frac{T \sin \theta}{a} = \frac{T \cos \alpha}{g} $$
and the angle is given by:
$$tan (\theta) = \frac{a}{g} $$
where ##r = \frac{v}{w}## and...
I know that to prove the total coriolis torque from the coriolis torque on a point mass is to express dm as a function of ##d\theta## and integrate from 0 to ##2\pi## and then the x component disappears due to orthogonality of sine and cosine. But i am stuck at other parts.
So i derived the moment of inertia about the axis of symmetry (with height h) and I am confused about the perpendicular axis theorem.
The problem ask to find the moment of inertia perpendicular to axis of symmetry
So the axis about h, i labelled as z, the two axis that are perpendicular to z, i...