But I've done that...in the previous posts. The problem is that I have 2 unknowns. In order to get v_f(velocity station+meteor after impact) I must know v_1(initial velocity of the meteor)
Apart from the speed of the meteor I have to calculate the perigee velocity. The answer for the perigee velocity is V_max = \frac{2m_2}{m_1+m_2}\sqrt{\frac{KM}{R}}This is the velocity calculated by me in the previous post. I used the conservation of angular momentum but I am not sure if that's...
The velocity (space station+meteor) after the impact wouldn't be the perigee velocity?Isn't angular momentum conserved(initial angular momentum in the circular orbit-final angular momentum at perigee)? For the circular orbit θ would be 90 . The same happens at perigee,right? Can't I find this...
This is what I've got so far:
Applying the conservation of linear momentum for the space station and the meteor:
$$\vec{p_i} =\vec{p_f} => m_1\vec{v1}+m_2\vec{v2}=(m_1+m_2)\vec{v_f}$$From this I should derive the relationship for v1-the speed of the meteor before hitting the space station but...
But didnt'I do that?Using conservation of linear momentum was my first idea and it is written in my first post but you said I can't treat them as scalars...
Before the collision the angular momentum of the space station is $$L_i = m_2 v R$$ where v is the circular velocity $$v = \sqrt{\frac{KM}{R}}$$
I have one question. How about the final angular momentum of the space station?I mean after the collision the meteor and the space station end up...
So I have the radial velocity of the meteor - the vector is pointing to the center of the Earth,right?
If I understand correctly the reason why I can't apply the conservation of momentum is because that radial velocity of the meteor is not parallel to the space station's velocity. I should...
Homework Statement
Hello! Suppose a meteor was approaching the Earth along a distance that passes through the Earth's center.I have a space station that moves around the Earth in a circular orbit (radius R)The meteor hit the space station and becomes incorporated.After the impact the space...
Ok,so my idea was:ω = Δx/ΔT where ω = 0,98 degrees/per day and ΔT=16 days. From here I get the arc length made by the Sun in 16 days from the equinox. Then I calculated what fraction represents this number from the total 360) =>f = 4,35% Taking into consideration the fact that the maximum...
After using some spherical trigonometry although you told me there's no need for that I've found this relationship between declination,latitude and the angle that the setting sun makes with the horizon: cos angle = sin latitude/cos declination. So at the equator at a solstice the angle is...
At equinox,yes. The angle ACB which the Sun makes with the horizon would be 90 but that angle is actually 90-latitude so sin ACB=AB/BC becomes: cos latitude=AB/BC. But this happens at equinox. Shouldn't there be a general relation between declination,latitude and this angle ACB?