Recent content by anaisabel

In when comes to length of the cocrodile, I haven't gotten that far because I can't solve the integral. I have tried to solve it, and I understand now why you have to separate in two intervals, from 0 to pi/4 and pi/4 to pi/2, because when you perform tha change of variable and change the limits...

I have forgotten a bit of my calculus, so I know the distance is the same, but if i don't know why it would complicate?.

Can you elaborate a bit more, i am not understanding very well.

Sorry , my handwriting is a bit messy, but basically he integrates fron 0 to pi/4 and then from pi/4 to pi/2. The length of the crocodile isn't really relevant, i just wrote the problem for some context. What i really want to know is how to solve that integral. I know you have to change...

equation i need to proof. the N in here, is the avarege number of particles, N0 is the total number of particles,V is total volume, v0 I am not quite sure what it is because it isn't mentioned in the homework, but I am assuming it is the volume of which space.

no problem, thanks for helping:)

I think my mistake is considering a range of E+ ΔE and E-ΔE, which in that case. it doesn't appear the (1/2), but if I consider the range E+ ΔE and E , then that factor (1/2) appears, so I think that's the issue.

the book in question is kardar particles, section 4.4, ideal gas. Kardar considers the integral the volume of hypersphere of dimension d with thickness ΔR. In that case, the general formula for N particles, is 3D, because the integral doesn't depend on the position , so your only integrating the...

If you look at textbooks , when writing the integral they always use the dimension that is applied to the situation. So in the case of the ideal gas is 3d and in the final formula they use 3d not 2d, I will show what I did, it is the bottom of the page. If i use 5d instead of 6d, I will not...

Well, I understand that but coming to that conclusion has to come from the calculations right? I know I am integrating in a 6 dimensional space, dxdydzdpxdpydpz, so when applying the formula I have to use 6d not 5d,because of the integral. But later on after thinking a bit more I realized that I...

ia

yes ρ is r, is basically the radius, it is the notation I am used from my course, but it is the same thing. So after I calculate the integral , what manipulation I need to do to come to conclusion that condition 2 in my file is valid, even when I isolate the ratio of the second derivate of...

I have attached a new file with more information, I hope it clarifies your first question, I haven't study jeffimenko equations, it wasnt mentioned in much detail in my electromagnetism course.

Hi, thanks for answering I have a few questions about what you said, I have attached a new file with a few additions for you see what I am doing, I can't seem to understand a few things.