Your overcomplicating things, I assume the treasure is located at each point turning point. The first treasure point (third on your list) is the easiest it's located at 12m and 0°, when it says turn 90° your are turning on a right angle to your right.
That cause a problem then I was the scattering cross section is proportional to Mfi and
|M_{fi}|^2 /propto 1 / (q^2 + m^2)^2
Starting from the definition of q = p_{final} - p_{initial}.
Show that the angular dependence of the scattering is then given simply by the Rutherford formula:CS=...
If I show something that a cross section is proportional to:
1 / (16p^2 sin^4( x) + 8mpsin^2 (x) + m^2)
does it imply that the cross section is proportional to
1 / sin^4 (x) as well?
Thanks.
I have a similar question, for electron-proton collision and I'll try to post my full working as I'm not really sure on these problems at all. Could someone check my answer please.
An electron with with total energy E collides with a proton at rest
e + p -> e + p + X, find the...
A Proton, m_{1} with Kinetic energy T = 200MeV strikes a stationary proton in the lab frame.
p + p -> p + p + X
what is the maximum mass of X, which can be produced.
I think I need to make use of E^2 - P^2 c^2 is invariant.
and
In S: E = (m_{1} + m_{0})c^2 , p = p_{1}
In S ' ...
2000 millitesla setting, it readsi 100 does this mean the field is 0.2T or 0.1T? I was pretty sure it was 0.2T but a demonstrator said the field had a maximum of ~1T but I'm getting a max of 2T.
I tried asking this question in the maths help, but am still stuck.
Q. For a simplified model of a proton's charge distribution, (where R can be considered as some characteristic "size" of the proton): \rho (r) \propto (1/r)Exp(- r / R) where R is some characteristic size of the proton...