Thanks, done that. I found some basic template of how it works and I modified it so that it know works. As per your suggestion, I used two PHP files and showed the users post as an iframe of the post they sent to be put on the website. I probably didn't explain that very well but just know that...
Thanks for the link but this only describes the existence of what I need. Do you know any websites for the code I'm talking about, or maybe you know yourself?
Hi,
So what I'm trying to do is enable visitors to the site pesterlog.tk, provided they have the correct login details, to change the code on the site. So say there was a page pesterlog.tk/user1, if user1 visited the page, (s)he could just enter the login details and change the code on...
I think I see why it works; because when you have a common factor of n and m, say 2, it's going to have two perfect corners (where it goes directly through a corner of a plank without touching any other plank) which is where I first derived the n+m-1 thing. But then obviously I had to account...
Yeah, sorry; my ruler skills are somewhat lacking.
Ok, so I thought about the common factor thing and the only thing I could come up with was n+m-hcf(n,m). This seemed to work for all of the ones that I tried.
Funny thing is: I used a ruler. :/
The cable has to be straight.
So, are you saying that there is or there isn't a formula that is consistent for all values of n and m? Also, how do I work out the formula; I'm not really sure where to go from where I am.
A door company makes doors out of square wooden panels. After installing many doors, they are asked to install a security cable that runs diagonally from the top right to the bottom left. With an n*m door, how many panels need to be lifted to place the security cable?
So what I did at first...
In the book it looks like this: \Sigma∞n=-1/12
Although I can't get it to look right using the formatting available to me. The ∞ should be sitting on top of the Sigma, and the n should be adjacent to it. Then there's also an n=1 that is just beneath the Sigma. Obviously this is all followed...