Recent content by alan1592

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    Coulombs Law solving for electrostatics force

    Sure I can do that. First i converted the givens to coulombs then the two outside spheres i got there information and then plugged them into the formula F=kq1q2/D2 for both sides but still i got the wrong answer
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    Coulombs Law solving for electrostatics force

    My attempt is in the picture. I converted everything and then used the equation F=KQQ/D^2 and stuff but idk what to do after that.
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    Voltage drop and current for each resistor

    Yeah he was very helpful to me too. I deff learned how to do the problem and that's what i wanted. Thanks man!
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    Coulombs Law solving for electrostatics force

    Homework Statement A small spehere with charge of +6.0uc is located near two other small charged spheres. A -3.0uc sphere is located 4.00 cm to the right and a +1.5uc sphere is located 3.00 cm to the left. Determine the resultant electrostatics force on the 6.0uc sphere. Correct answer is...
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    Voltage drop and current for each resistor

    Im looking to find those items. The voltage drop and the current. I don't know how.
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    Voltage drop and current for each resistor

    Homework Statement heres a picture of the problem. Please don't give me the answer just tell me what are the steps to complete it. thanks. http://i307.photobucket.com/albums/nn296/alan1592/download-1.jpg Homework Equations V=IR The Attempt at a Solution 1/6+1/3=2 Ohms
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    What is the current through resistor 2 in a series circuit?

    Ok I got the right answer. I got the total resistance and divide it by the volts and i got the current. Thanks guys! What if I have another question on this same sort of problem do i make another thread? Or should i just ask here?
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    What is the current through resistor 2 in a series circuit?

    Homework Statement First problem is a series circuit with 3 resistors. R1,R2,R3 is 3.0 ohms. This is all powered by a 3.0 V battery. What is the current threw resistor 2? Homework Equations V=IR The Attempt at a Solution 3.0=I(3.0) Divide both sides by 3.0 and I got 1 ...
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