Recent content by AHinkle

Homework Statement A constant-volume gas thermometer is cal- ibrated in dry ice (which is carbon dioxide in the solid state and has a temperature of −80◦C) and in boiling ethyl alcohol (78◦C). The two pressures are 1 atm and 1.542 atm. What value of absolute zero does the cali- bration...

Homework Statement A woman with a mass of 70 Kg stands at the rim of a horizontal table having a moment of inertia of 490 kg*m^2 and a radius of 1.4 m. The turntable is initially at rest and is free to rotate about a frictionless, vertical axis through it's center. The woman then starts...

how (in what form) would i write equations for the pulleys.. would it be F = ma or would it be in the form \tau=I\alpha? i've got to leave for work but would they look like \tau = T1 - (something) = I\alpha i mean would they be analagous to F = ma equation but with diff. vars? with...

Homework Statement Homework Equations \SigmaF = ma \Sigma\tau=I\alpha ? The Attempt at a Solution m1 = 1 Kg m2 = 8 Kg \theta = 33 degrees mpulley = 7 Kg rpulley = .11 m \mu = 0.27 g = 9.8 m/s2 My attempt, I'm falling behind in class due to an illness and I can figure this...

did you actually do sin(30) ? maybe you just messed up the angle it looks like you did it right for the most part..

We have the same homework service I am pretty sure... mine was due today so here's how I did it. Since there is no friction on the first part of the problem, mechanical energy is conserved and you can use Ui+Ki=Uf+Kf Ui= (1/2kx2 + mghi) where hi = 0 I put the reference point a the top of the...

okay k is the spring constant which is given above 14 N/cm or 1400N/m if you convert it like I did. so you know that initial potential energy is the potential energy in the spring plus the gravitational potential energy. If you set you reference point there you can say that gravitational...

actually i checked the answer and .8350 m/s is correct! I found out what i did wrong. I converted from centimeters to meters incorrectly in my first work calculation and that threw everything off.

1/2kxf2-1/2kxi2=1/2mvi2 1/2(5x106)(-.0167)2-1/2(5x106)(0)2=1/2(2000)vi2 vi = .835m/s? aww crap... i got a sign or something mixed up somewhere or i just don't understand what orientation i need to put all the parts together in

do you mean Fspring=-kx and the work done by a spring is Ws=\int(-kx) dx = 1/2kxf2-1/2kxi2

Homework Statement An automobile of mass 2000 kg is driven into a brick wall in a safety test. The bumper behaves like a Hooke’s-law spring. It has an effective spring constant of 5 × 106 N/m, and is observed to compress a distance of 1.67 cm as the car is brought to rest. What was the...

Homework Statement A softball pitcher rotates a 0.236 kg ball around a vertical circular path of radius 0.633 m before releasing it. The pitcher exerts a 30 N force directed parallel to the motion of the ball around the complete circular path. The speed of the ball at the top of the...

okay i fixed everything, please help me out. The homework is already turned in, I just want the knowledge..

im trying to get it to work, and the symbol stuff is screwing up.. how do i delete the post and start over?

Homework Statement Homework Equations \SigmaF=ma ac=(v^2/r) f = \muN The Attempt at a Solution \SigmaFradial= (radial-coordinate of normal force) + (radial component of friction) = ((mass)(velocity^2)/(radius)) \SigmaFy= (y-component of normal force) - (y-component of friction) =...