Recent content by ace8888

yes, it is. Thank you for your help.

4.1micro seconds.

##V_A## = -5 ##V_B## = 15 The general DE eq after you account for the initial not equal to zero is v(t) = ##V_s## + (##V_o## -##V_S##)##(1-e^{-t/RC})##

This is my understand, initially the current will be the maximum value when t=0 and when the capacitor getting up to the value of the source, there will not be any current (time to infinity). I've graphed the current vs. time As for your question about the value of current when t=0. This is...

Ok, so when t=0 the capacitor is initially charged to -5V but the source is 10V which mean it will try to charge the capacitor to match it value. How does the discharge and charging work at the same time? If it can;t be done, how does the capacitor discharge while the voltage source is still...

No current b/c the switch is open. After the switch closes, there is current flowing but there is no voltage across the capacitor yet. I still don't understand where you said the equation that I've used is wrong.

It said that the switch has been open for a "long time". Shouldn't the capacitor at t=0 (meaning right after the switch closes), still sitting at 0V at the start and if T>>0 (like infinity) the capacitor will charge up to the source voltage which is 10V so isn't the equation i used is correct...

Typo, yes it is the natural exponent. I don't know why but i was thinking exponent and typed log. They are inverse of each other.

The voltage will begin to charge the capacitor to the match the source when the switch closed for a long period of time. They wanted to know how long it would take for the capacitor voltage to equal 2.5V, I am taking it that they are asking how long it would take the voltage source to charge the...

Homework Statement At initially, the switch is open meaning there is no current flowing. So how does the capacitor is initially charge to -5V? and what does a negative voltage capacitor means? I thought it is only when the switch is closed (t=0) that when the capacitor is being charged...

thanks!

Homework Statement Hi, I've run into two different equations for the voltage of a typical RC circuit, one resistor, and one capacitor. Please explain the different between the two. One has a 1 - the natural log and the other one doesnt. Homework Equations 1. V(t) = Vo*e^(-t/RC) 2. Vc =...

Ia and Ib moving in opposite of Is so that should be Ia + Ib - Is = 0. where do they get the Ia + Ib = -Is from?

< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown > Hi, I couldn't figure out from the equation that relate the current source IS to IA and IB. If both IA and IB is coming from the same direction and the positive terminal has been predicted...