so really the answer would be 0.5*mu(0)*i*n
i think i get it. superposition of two semi-infinite solenoids counts as a infinite solenoid. so i guess if you find the magnetic field at the non infinite end of a semi-infinite solenoid then it would be just half of the formula.
sweet. i get it...
Homework Statement
Suppose your physics lab class lasts for a very long time - long enough for you to wind a semi-infinite solenoid. (That spool of copper wire is the gift that keeps on giving.) What is the on-axis magnetic field at the end of the solenoid closest to you (ie., not at...
i know that equation 1. amperes law i think , is used for solenoids with no core
and the second is for a segment of current wire.
i picked these 2 because it seemed like they would satisfy the terms that was required in the answer. except i still don't know where i could include variables a...
Homework Statement
http://i27.lulzimg.com/ac8f155fa0.jpg
[PLAIN][PLAIN]http://i27.lulzimg.com/b5f4ac2fce.jpg
Homework Equations
1. B = ((mu(0) * N * I )) / L ,, 2. (mu(0) / 4pi)*((I*(delta(S) cross r(direction)))/r^2)
The Attempt at a Solution
im not really sure which...
ok so i refreshed my memory a little, by looking at my notes. I've tried part (a), and got the following:
condition (0) => A = [0 0;0 0] and A(Transpose) = [0 0;0 0], so satisfied
condition(1) => A = [ a1 b1; c1 d1] and B = [ a2 b2; c2 d2]. A(Tran) + B(tran) must be equal to (A+B)(tran)...