OK, using the reaction, there is 1 mooe of ethanoic acid with 1 mooenof sodium hydroxide.
Solution A:
2 moles of ethanoic acid with 1 mole of sodium hydroxide.
Solution B:
1 mole of ethanoic acid with 1 mole of sodium hydroxide.
One exanple I found was to find the pH of a buffer solution containg ##acm^3# of ##bmol## ##dm^{-3}} ethanoic acid with ##xcm^3# of ##ymol## ##dm^{-3}} sodium ethanoate. None involving an acid with a base, only acid with salt.
The only equation I know of that would work here would be ##K_a=\frac{[H^+]CH_{3}COO^-]}{[CH_{3}COOH]}## but doesn't count in ##[NaOH]##
Unless there is another word for electroneutrality, then I've probably never heard of it before. Maybe I have by definition but not by name.
Whenever I try to find similar questions, I only get unrelated questions involving a weak acid and a (usually sodium) salt based off of the conjugate base of the acid.
Not sure if its right or not, but after using Ka and an ICE table, I got a concentration ratio of CH3COOH:NaOH:CH3COONa as:
Solution A - 73:74:1
Solution B - 105:52:1
It seems like solution A is the buffer contains around equal concentrations of ethanoic acid and sodium ethanoate at...
I know that, as I said, I'm fine with the other questions in the image except for that one.
The questions in the image come under 'Buffer solutions' which covers the following:
What a buffer solution is
Calculating the pH of a buffer solution
A buffer solution made from a weak acid and...
Not sure how much of this, or what bits, was needed but I wrote as much as I thought would be.
1. In the reaction, for stoichiometry it was 1, in terms of actual moles, 1.
2. In the reaction, for stoichoimetry it was 1, in terms of actual moles, 2.
Well, for the forward reaction (assuming...
How would I do that, especially for after? Look, I said I'm not good with the maths and equations involved with buffers, I'm trying to make sure I know what I need to know for the exam. I don't want to write something down which is completely wrong and useless and look stupid, I just want make...