Sure, so the photo eye requires that power +/- inefficiencies. I guess i am hung up on how it does this - Where is the reduction of resistance in order to allow more electrons to flow (higher amps). what component of the photo eye allows this to happen.
I don't know much about non-linear circuits, can you elaborate on how current can go up as voltage goes down? voltage is the "pressure" and Current is "flow"
I was reading the specs on a photo eye and it states its current consumption
65 mA at 24v
120 mA at 12v
both situations end up with roughly 1.56 VA of power...how does it draw more current with less voltage applied. If V=IR, the only way i see it is the resistance of the system must lower...