Recent content by 6c 6f 76 65

  1. 6c 6f 76 65

    Are A[X, Y]/(XY) and A[X]⊕A[Y] Isomorphic?

    Thank you for the reply! Sorry if I'm wasting your time, but I don't get what you mean by copy? (Is ⊕ the same as ×?) And ##A[X, Y]/(XY)## means, as far as I know, all polynomials, with coefficients from A, of variable X and Y. Mod XY means, XY = 0, so shouldn't the new ring be functions of only...
  2. 6c 6f 76 65

    Are A[X, Y]/(XY) and A[X]⊕A[Y] Isomorphic?

    Homework Statement My textbook says that A[X, Y]/(XY) is a subring of A[X]⊕A[Y], but aren't they isomorphic? (A is any commutative ring) Homework Equations 1st Ismorphism Theorem The Attempt at a Solution I can construct the map φ: A[X, Y] → A[X]⊕A[Y] f(X)+g(Y)+h(X, Y)*X*Y → f(X)+g(Y), this...
  3. 6c 6f 76 65

    Separable partial differential equation

    Have you typed the the first equation correct? Because if not w_φ=0, and for the rest: remember that when you differentiate / integrate with respect to r you may have lost a function of θ.
  4. 6c 6f 76 65

    Calculating Rotational Volume for Enclosed Area by Revolution Around Y-Axis

    Correct! Correct! Almost correct, what is the height of the "inner cylinder"? Well, you can make it a little simpler by saying the volume you're interested in finding is composed by: - Volume bounded by: x=1, x=2, y=0, y=\frac{1}{2} then get V_1=\pi\int_0^\frac{1}{2} (2^2-1^2)dy =...
  5. 6c 6f 76 65

    Calculating Rotational Volume for Enclosed Area by Revolution Around Y-Axis

    Seems like you're heading in the right direction! As you creatively thought removing the cylinder is the key, now in order to compute the whole volume divide it into: - The volume of the "large thin cylinder", bounded by x=0, x=2, y=\frac{1}{2} (is the radius constant here?) - The volume of the...
  6. 6c 6f 76 65

    Calculating Rotational Volume for Enclosed Area by Revolution Around Y-Axis

    Imagine seeing the rotated figure from above, it kinda looks like a volcano. Try to make a radius from the origin: one from the O to the yellow line, and one from O to the green line. How long will both of these radii be (as a function of x, then make the substitution y=\frac{1}{x})?
  7. 6c 6f 76 65

    How Do You Calculate the Volume of a Rotating Body Around Different Axes?

    Think of it this way: You'll get the volume of the figure if you first find the volume under the purple line and the remove the volume between the purple line and the blue curve
  8. 6c 6f 76 65

    Calculating the zeta function over a hypersurface in project

    Homework Statement Calculate the zeta function of x_0x_1-x_2x_3=0 in F_p Homework Equations Zeta function of the hypersurface defined by f: \exp(\sum_{s=1}^\infty \frac{N_s u^s}{s}) N_s is the number of zeros of f in P^n(F_p) The Attempt at a Solution My biggest struggle is finding N_s...
  9. 6c 6f 76 65

    Evaluating the Svein-Graham Sum

    I was looking for a more analytic expression like \sum_{i=1}^n i = \frac{n(n+1)}{2}. Maybe it's possible to find yet another connection to the Bernoulli numbers? But thank you nevertheless!
  10. 6c 6f 76 65

    Evaluating the Svein-Graham Sum

    Good evening dearest physicians and mathematicians, I recently came across the so-called "Svein-Graham sum", and i wondered: is it possible to find a simple formula for evaluating it? \sum_{i=0}^k x\uparrow\uparrow i = \left .1+x+x^x+x^{x^x}+ ... +x^{x^{x^{x^{.^{.^{.^x}}}}}}\right \}k
  11. 6c 6f 76 65

    Faraday's Dynamo & kinetic energy

    I=\frac{1}{2}m R^2, thank you so much!
  12. 6c 6f 76 65

    Faraday's Dynamo & kinetic energy

    Thank you so much! Here's what I got: \frac{dK}{dt}=-\frac{B^2 R^4 \omega^2}{4 R_\Omega}=-\frac{B^2 R^2}{2 m R_\Omega}K, used that K=\frac{1}{2}m \omega^2 R^2 Solution for diff. equation: K=K_0 e^{-\frac{B^2 R^2}{2 m R_\Omega}t} \frac{1}{2}=\frac{K}{K_0}=e^{-\frac{B^2 R^2}{2 m R_\Omega}t}...
  13. 6c 6f 76 65

    Faraday's Dynamo & kinetic energy

    \frac{dKE}{dt}=-\frac{(\frac{B R^2 \omega}{2})^2}{R_\Omega}
  14. 6c 6f 76 65

    Faraday's Dynamo & kinetic energy

    Sorry, I don't quite know what you mean. The KE and the electrical power produced is linked via the angular velocity with the formula: W=\frac{(\frac{B R^2 \omega}{2})^2}{R_\Omega}t=\Delta KE
Back
Top