My mistake for not completing my answer.
And yes, that's what i meant, When -8(xin) was greater than -3 then the Vout would be +16V
Then that would be Xin < 0.375 for it to be +16V
But the answer is saying the opposite.
Homework Statement
https://physicsforums-bernhardtmediall.netdna-ssl.com/data/attachments/73/73750-4bf3d2aa03a724fcf0b13a6b1111902f.jpg The Attempt at a Solution
V+ > V- for Vout to be +16V
V+ < V- for Vout to be -16V
V+ = -8x(in)
V- = (-15x18)/30 + (15x12)/30 = -3
My attempt on it was that...
I already posted this, but it was on the wrong section.
This is from the 2009 HSC exam. (I'm in Australia)
I checked the answers and found that electric field strength was
E = 100/0.10 = 1000V/m
My question is, what would the electric field strength be if the positively charged plate was...
I just realized that I shouldn't have posted here. Sorry about that.
But another question
http://www.regentsprep.org/Regents/physics/phys03/aparplate/plate3.gif
In this gif where
E = V/d
Shouldn't it be E = 2V/d
as there is voltage going to the positive and negatively charged plate for example...
This is from the 2009 HSC exam. (I'm in Australia)
I checked the answers and found that electric field strength was
E = 100/0.10 = 1000
My question is, what would the electric field strength be if the positively charged plate was +100V instead of 0V
Would it be 200/0.1 = 2000?
Is the formula E...