
#1
September 23rd, 2018,
12:34

September 23rd, 2018 12:34
# ADS
Circuit advertisement

Pessimist Singularitarian
#2
September 23rd, 2018,
13:20
Let's go through this step by step...can you find the area of $ \displaystyle \triangle ABC$ ?

#3
September 23rd, 2018,
13:22
Thread Author
Originally Posted by
MarkFL
Let's go through this step by step...can you find the area of $ \displaystyle \triangle ABC$ ?
3200cm^2

Pessimist Singularitarian
#4
September 23rd, 2018,
13:25
Originally Posted by
Yazan975
That's not correct...how did you arrive at that answer?

#5
September 23rd, 2018,
13:25
Thread Author
Originally Posted by
MarkFL
That's not correct...how did you arrive at that answer?
1600cm^2?
For 3200 I multiplied Base and Height but didn't divide by 2

Pessimist Singularitarian
#6
September 23rd, 2018,
13:27
Originally Posted by
Yazan975
1600cm^2?
For 3200 I multiplied Base and Height but didn't divide by 2
Okay, good...so what must the area of $ \displaystyle \triangle AED$ be?

#7
September 23rd, 2018,
13:28
Thread Author
Originally Posted by
MarkFL
Okay, good...so what must the area of $ \displaystyle \triangle AED$ be?
xy/2 cm^2

Pessimist Singularitarian
#8
September 23rd, 2018,
13:31
Originally Posted by
Yazan975
Yes, that's correct in terms of \(x\) and \(y\), but we should also be able to assign a numeric value to its area based on the fact that the areas of the two shaded regions are the same.
This will give us an equation...can you state it?

#9
September 23rd, 2018,
13:33
Thread Author
Originally Posted by
MarkFL
Yes, that's correct in terms of \(x\) and \(y\), but we should also be able to assign a numeric value to its area based on the fact that the areas of the two shaded regions are the same.
This will give us an equation...can you state it?
xy/2 cm^2 = 800
xy = 1600
Is that right?

Pessimist Singularitarian
#10
September 23rd, 2018,
13:39
Originally Posted by
Yazan975
xy/2 cm^2 = 800
xy = 1600
Is that right?
Excellent!
Okay, now the next thing I notice is that within $ \displaystyle \triangle ABC$ there are two similar triangles, with $ \displaystyle \triangle AED$ being the smaller of the two. This means we may state:
$ \displaystyle \frac{y}{x}=\frac{40}{x+10}$
Do you see where this comes from?
What I would do here is solve both equations we now have for \(y\), and equate the two results to get an equation in \(x\)...can you state this equation?