
#1
April 22nd, 2016,
11:23
Hello
is my proof be correct ?
I wish to prove by induction that ${\psi}_{n}(x)\le F(n)$ , $x\in[a,b]$ ......... (1)
Let there exists a function $f(x,n)$ such that if ${\psi}_{n}(x)\le f(x,n) $ then ${\psi}_{n}(x) \le F(n)$ .
I know that (1) is true for $n=1$ i.e. ${\psi}_{1}(x)\le f(x,1)\le F(1)$ ,
and I was able to prove that
${\psi}_{n+1}(x)\le F(n+1)$ , $x\in[a,b]$
would this implies ${\psi}_{n}(x)\le F(n)$
thanks

April 22nd, 2016 11:23
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#2
April 23rd, 2016,
14:04
Originally Posted by
sarrah
I wish to prove by induction that ${\psi}_{n}(x)\le F(n)$ , $x\in[a,b]$
Please provide the definitions of $\psi_n$, $F$, $a$ and $b$.