
MHB Master
#1
March 26th, 2020,
00:24
$\tiny{166.2.6.5}$
Find y'
$$x^24xy+y^2=4$$
dy/dx
$$2x4(y+xy')+2yy'=2x4y4xy'+2yy'=0$$
factor
$$y'(4x+2y)=2x+4y=$$
isolate
$$y'=\dfrac{2x+4y}{4x+2y}
=\dfrac{x+2y}{2x+y}$$
typo maybe not sure if sure if factoring out 4 helped
Last edited by karush; March 26th, 2020 at 19:15.

March 26th, 2020 00:24
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#2
March 26th, 2020,
01:11
Originally Posted by
karush
$\tiny{166.2.6.5}$
Find y'
$$x^24xy+y^2=4$$
dy/dx
$$2x4(y+xy')+2yy'=2x4y4xy'+2yy'=0$$
factor
$$y'(4x+2y)=2x+4y=$$
isolate
$$y'=\dfrac{2x+4y}{4x+2y}
=\dfrac{x+2y}{2x+y}$
typo maybe not sure if sure if factoring out 4 helped
What you've done is correct.