
#1
January 29th, 2020,
07:01
bP = 1,0 = 1.48A + (0.72 * (1A))
How does one solve for A in this given situation?

January 29th, 2020 07:01
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#2
January 29th, 2020,
07:40
Originally Posted by
Luclucluc
bP = 1,0 = 1.48A + (0.72 * (1A))
How does one solve for A in this given situation?
What is your equation?
Is it:
\begin{cases}
bP = 1.0 \\
1.0 = 1.48A + (0.72 * (1A))
\end{cases}
Or is it:
\begin{cases}
bP = 1, \\
0 = 1.48A + (0.72 * (1A))
\end{cases}

#3
January 29th, 2020,
09:18
Assuming that your equation is $ \displaystyle 1.48A+ (0.72(1 A))= 0$, first expand the multiplication: $ \displaystyle 0.72(1 A)= 0.72 0.72A$.
That makes the equation $ \displaystyle 1.48A+ 0.72 0.72A= 0$.
Now, combine the two "A" terms: 1.48A 0.72A= (1.48 0.72)A= 0.76A.
That makes the equation $ \displaystyle 0.76A+ 0.72= 0$.
Subtract 0.72 from both sides: $ \displaystyle 0.76A= 0.72$.
Finally, divide both sides by 0.76: $ \displaystyle A= \frac{0.72}{0.76}= 0.9473$....
Last edited by Klaas van Aarsen; January 29th, 2020 at 11:05.
Reason:
Correct LaTeX Code