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  1. MHB Apprentice

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    #1
    bP = 1,0 = 1.48A + (0.72 * (1-A))

    How does one solve for A in this given situation?

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    #2
    Quote Originally Posted by Luclucluc View Post
    bP = 1,0 = 1.48A + (0.72 * (1-A))

    How does one solve for A in this given situation?
    What is your equation?
    Is it:
    \begin{cases}
    bP = 1.0 \\
    1.0 = 1.48A + (0.72 * (1-A))
    \end{cases}
    Or is it:
    \begin{cases}
    bP = 1, \\
    0 = 1.48A + (0.72 * (1-A))
    \end{cases}

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    #3
    Assuming that your equation is $ \displaystyle 1.48A+ (0.72(1- A))= 0$, first expand the multiplication: $ \displaystyle 0.72(1- A)= 0.72- 0.72A$.

    That makes the equation $ \displaystyle 1.48A+ 0.72- 0.72A= 0$.

    Now, combine the two "A" terms: 1.48A- 0.72A= (1.48- 0.72)A= 0.76A.

    That makes the equation $ \displaystyle 0.76A+ 0.72= 0$.

    Subtract 0.72 from both sides: $ \displaystyle 0.76A= -0.72$.

    Finally, divide both sides by 0.76: $ \displaystyle A= -\frac{0.72}{0.76}= 0.9473$....
    Last edited by Klaas van Aarsen; January 29th, 2020 at 11:05. Reason: Correct LaTeX Code

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