• scottkoz20

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Re: Multiple consists of only 6's and 7's

Our solution is very much like yours.

We divided the numbers into 3 categories:
(1) Odd numbers. Use Pigeon hole theorem to prove every

Satya Today, 05:45

learned this method in a CS FORTRAN class a long time ago ...

Let $x=20$

1HE1C = $x^4 + 17x^3 + 14x^2 + x + 12x^0$

skeeter Yesterday, 08:58

as we are not comfortable with base 20 let us convert to base 10 (digit by digit) and concert it back
1HE1C
JDF 0

1HE1C +JDF0= 2H7GC from calculator
By hand I couldn't get the H

Using
1
2
3

karush Yesterday, 00:31

Re: Dice probability

For #2, I got 150 from the ff:

number of choices for the number showing on the dice = 6
number of ways of choosing which 4 dice