• ## gnrx

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• ### Recent Forum Posts

#### Re: Proving limit by definition

Not quite, although you started correctly. The limit in this case is as $x\to\infty$, so you want to see what happens when $x$ gets large. This means

Opalg Today, 06:35

#### Re: Proving limit by definition

Hi Opalg! Do you think I got it correct?

goody Today, 04:38

#### Re: 299What is the acceleration

why did you do that? ...

... if originally, $x = \sin{t}-\cos{t}$, then $v = \cos{t} + \sin{t} = 0 \implies t = \dfrac{3\pi}{4}$

skeeter Yesterday, 19:28

#### Re: 299What is the acceleration

Wait! What do you mean by you changed it to v(t)? The particle's position is x(t) = sin(t) - cos(t) means that v = $\displaystyle \dfrac{dx}{dt}$. You can't just change

topsquark Yesterday, 17:53

#### 299What is the acceleration

$\tiny{299}$
For $t \ge 0$ the position of a particle moving along the x-axis is given by $v(t)=\sin t—\cos t$ What is the acceleration of the

karush Yesterday, 17:38