• ## balancedlamp

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• ### Recent Forum Posts

#### Re: 299What is the acceleration

why did you do that? ...

... if originally, $x = \sin{t}-\cos{t}$, then $v = \cos{t} + \sin{t} = 0 \implies t = \dfrac{3\pi}{4}$

skeeter Yesterday, 19:28

#### Re: 299What is the acceleration

Wait! What do you mean by you changed it to v(t)? The particle's position is x(t) = sin(t) - cos(t) means that v = $\displaystyle \dfrac{dx}{dt}$. You can't just change

topsquark Yesterday, 17:53

#### 299What is the acceleration

$\tiny{299}$
For $t \ge 0$ the position of a particle moving along the x-axis is given by $v(t)=\sin t—\cos t$ What is the acceleration of the

karush Yesterday, 17:38

#### Re: Proving limit by definition

Hi [unm]Goody[/unm], and welcome to MHB!

To prove that $\displaystyle \lim_{x\to\infty}\frac{x-1}{x+2} = 1$, you have to show that, given $\varepsilon > 0$, you

Opalg Yesterday, 14:52

#### Proving limit by definition

Hi, can anybody help me with this two limits? I have to prove them by the definition of limit. Thank you in advance.

goody Yesterday, 12:31