
#1
April 2nd, 2014,
19:32
I have a continuous function h(x) and the inequality h(b)<=0<=h(a). Can I apply IVT?

April 2nd, 2014 19:32
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#2
April 2nd, 2014,
20:01
Well, what are the hypotheses of the IVT? Are they satisfied in your case?

#3
April 2nd, 2014,
20:17
Thread Author
Originally Posted by
Ackbach
Well, what are the hypotheses of the IVT? Are they satisfied in your case?
Isn't it just that h(x) is continuous and if u is a number between h(b) and h(a),
h(b) < u < h(a), then etc etc. I didn't think I could, but I just wanted to see a variation of it.

#4
April 2nd, 2014,
21:34
Originally Posted by
TheDougheyMan
Isn't it just that h(x) is continuous and if u is a number between h(b) and h(a),
h(b) < u < h(a), then etc etc. I didn't think I could, but I just wanted to see a variation of it.
Exactly right. So you can conclude that there is a $c \in (a,b)$ (I'm assuming $a<b$) such that $h(c)=0$.