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  1. MHB Master
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    #1
    $\textsf{got ??? on the Greek notation. if Period = T}$
    \begin{align}
    \displaystyle
    Y_{tan}&=A\tan\left[\omega\left(x-\frac{\phi}{\omega} \right) \right]+B
    \implies A\tan\left(\omega x-\phi \right)+B \\
    T&=\left(\frac{\phi}{\omega}\right) \\
    PS&=\phi
    \end{align}
    $\textsf{so on:}$
    \begin{align}
    \displaystyle
    Y_{49}&=1+\frac{1}{2}\tan\left({2x-\frac{\pi}{4}}\right) \\
    T&=\frac{\pi}{2} \\
    PS&=\frac{\pi}{4}
    \end{align}


    $\textsf{not sure on this one} $
    Last edited by karush; November 3rd, 2016 at 19:19.

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    #2
    What is your question?

  3. MHB Master
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    #3 Thread Author
    Quote Originally Posted by HallsofIvy View Post
    What is your question?
    why is this in greek?

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