Work, Kinetic Energy, Spring, Friction Problem

In summary, a block of mass 2.5 kg slides from rest on a track with an elevated left end and a flat central part of length L = 10 cm. The track is frictionless except for the rough part of length D = 10 cm with a coefficient of kinetic friction uk = 0.20. The block's initial height is h = 40 cm and the spring constant k = 320 N/m. The block's speed before reaching the rough part is 2.8 m/s and its speed just before reaching the spring is 2.73 m/s. The work done on the block by the gravitational, normal and frictional forces is 0, 0, and -0.49 J respectively
  • #1
Tristin_noel
1
0
A block slides from rest, along a track with an elevated left end, a flat central part, into a relaxed spring, as shown in the figure. The curved portion of the track is frictionless, as well as the first portion of the flat part of L = 10 cm. The coefficient of kinetic friction between the block and the only rough part, D = 10 cm, is given by uk = 0.20. Let the initial height of the block be h = 40cm, its mass be m = 2.5 kg, and the spring constant k = 320 N/m. (Picture should be posted below.)

1. While the block slides through the flat central part of length L find:

a) The work done on the block by the gravitational force. = would you use W=mgh ?
b) The work done on the block by the normal force. = 0 bc the normal force is perpendicular to the displacement.
c) The work done on the block by the frictional force. = 0 bc no frictional force present
d) The speed of the block right before it reaches the beginning of the rough central part of length D. =2.8m/s used the eqautopn PE=KE , mgh=1/2m(vf^2-vi^2)

2) The block has now made it to the rough region of length D and will eventually slide head on into the spring at the end of the path. Over this region of length D, calculate:

e) The work done on the block by the gravitational force. = 0 bc perpendicular
f) The work done on the block by the normal force. = 0 bc perpendicular
g) The work done on the block by the frictional force. =-0.49J bc Wfriction=uk(mg)d
h) The speed of the block just as it reaches the spring. =2.73m/s using Vf^2-Vi^2=2(-ukg)d

3) Assuming the block compresses the spring by x, find:

i) The work done by the spring force. would you use W=1/2mVf^2 ?
j) The compression distance, x, of the spring. would you use W=kx and just solve for x?

https://s.yimg.com/hd/answers/i/6ae6d9b8385d4d3eb364c25c31aeb7d5_A.png?a=answers&mr=0&x=1425534324&s=478f148cd3470b7f93d03b19b2553c0b
 
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  • #2
The point of the exercise is to test/improve your understanding of conservation of energy and work.
Your questions are about what equations to use - you should use your understanding, which seems OK, to figure out the equations.
How would you go about answering your own questions? i.e. for (a) you want to know if the work due to falling a distance h under gravity is given by mgh.

How could you check? Perhaps by using the definition of work in terms of forces or in terms of the work-energy theorem?
Same for the work done by the spring.
 

Related to Work, Kinetic Energy, Spring, Friction Problem

1. What is work?

Work is defined as the force applied on an object multiplied by the distance the object moves in the direction of the force. It is a measure of the energy transferred to or from an object.

2. How is kinetic energy related to work?

Kinetic energy is the energy an object possesses due to its motion. The work done on an object is equal to the change in its kinetic energy. This means that when work is done on an object, its kinetic energy increases or decreases depending on the direction of the force.

3. What is the role of a spring in a work, kinetic energy, spring, friction problem?

A spring is a type of elastic object that can store and release mechanical energy. In work, kinetic energy, spring, friction problems, a spring can be used as a source of potential energy that can be converted into kinetic energy or work done on an object.

4. How does friction affect work and kinetic energy?

Friction is a force that opposes motion between two surfaces in contact. When an object is moving, friction acts in the opposite direction and reduces its kinetic energy. This means that more work must be done to maintain the same speed and overcome the frictional force.

5. How can we calculate the work done on an object in a spring, friction problem?

To calculate the work done on an object in a spring, friction problem, we can use the equation W = Fd cosθ, where W is work, F is the force applied, d is the distance the object moves, and θ is the angle between the force and the direction of motion. This equation takes into account the effects of both the spring and friction forces on the object.

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