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Gold3nlily
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Homework Statement
How much work is done by a force= (2x)i N + (3)j N with x in meters, that moves a particle from a position (initial) = (2m)i + (3m)j to a position (final) = (-4m)i + (-3m)j?
Answer:
- 6 J
Homework Equations
Work = integral of Force
The Attempt at a Solution
W = [x^2] i + [3x] j
W = [4^2 - 2^2] i + [3(-3) - 3(3)] j
W = 12 i -18 j
W magnitude = 21.6J
I realize I am doing this wrong becasue the Magnitude will always be positive and the answer (from back of book) is negative.
I tried this in a similar way where I took the difference between the two position vector and then placed it in the integral
rd = (-6) i + (-6) j
Got W = 36 i + 18 j
still wrong.
Help, pretty please?