Why Is Calculating the Normalization Constant in Quantum Mechanics Challenging?

In summary, the student was trying to find the normalization constant for quantum mechanics. He got stuck when he read the question incorrectly and realized he was supposed to double the constant when solving for A.
  • #1
lol physics
11
0
Hi, 2nd year physics student here

doing a past paper on quantum mechanics everything is going nice and dandy then this happens..

question: prove that the normalisation constant A is given by A = [tex]\frac{1}{2^1^/^2}[/tex] ([tex]\frac{a}{\pi}[/tex])^1/4

ok seems fairly straight forward but i keep getting this A = [tex]\frac{1}{2^1^/^2 (a*\pi)^1^/^4}[/tex]

wave function ------> [tex]\Psi[/tex] (x,t) = A*2*[a*x*(e^-ax^2/2)(e^-3/2iwt)

useful integral: Inegration from - infinity to + infinity of x[tex]^{2}[/tex]*e[tex]^{-C}[/tex][tex]^{x^{}2}[/tex] dx = [tex]\frac{1}{2}[/tex] ([tex]\frac{\pi}{C^{3}}[/tex])[tex]^{\frac{1}{2}}[/tex]

any flawless mathematicians out there..?
 
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  • #2
Welcome to Physics Forums :smile:

lol physics said:
any flawless mathematicians out there..?
Nope ... there's no such thing!

Can you show the integral you set up to calculate A?
 
  • #3
any one?
 
  • #4
If you show more steps of your work, we might be able to spot where you went wrong.
 
  • #5
you have the wave function, you have what the answer should be and you have the identity integral needed to solve this. I gave you the answer i kept receiving, my friend who is a theoretical physicist also received the same answer, if you do in fact obtain the right answer can you show a step by step of how it was obtained, if you received the same answer as us then there may be a problem with the actual question.
 
  • #6
could have something to do with odd functions and even functions. I got a problem like this. It ended up being 0 because it was an odd function and with even functions you double.
 
  • #7
lol physics, I agree that A is proportional to a-1/4
 
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  • #8
If you think the problem is wrong, why don't you just plug in their normalization constant and see if you get 1? If you don't get 1, then there is probably something wrong.
 
  • #9
found the problem sorry, i was reading the question wrongly. you can use this thread as an example of why you should read questions properly, i thought the square root was covering the whole wave function but it was only covering one of the constants. thank you for all your help.
 

Related to Why Is Calculating the Normalization Constant in Quantum Mechanics Challenging?

What is a "Dang normalisation constant"?

A "Dang normalisation constant" is a mathematical term used in statistics and data analysis. It refers to a constant value that is used to scale a probability distribution so that the total probability equals one.

Why is it called a "Dang normalisation constant"?

The term "dang" is often used as a slang term to express surprise or frustration. In this context, the phrase "dang normalisation constant" may have been coined by scientists or statisticians who were frustrated by the need to constantly use this constant in their calculations.

What is the purpose of a "Dang normalisation constant"?

The main purpose of a "Dang normalisation constant" is to ensure that the probabilities in a probability distribution add up to one. This is important because it allows for meaningful comparisons between different probability distributions.

How is a "Dang normalisation constant" calculated?

The calculation of a "Dang normalisation constant" depends on the specific probability distribution being used. In general, it involves integrating the probability distribution function over its entire range of values and then using this value to scale the distribution.

What happens if the "Dang normalisation constant" is not used?

If a "Dang normalisation constant" is not used, the probabilities in a distribution will not add up to one. This can lead to incorrect interpretations of the data and make it difficult to compare different probability distributions. Therefore, it is important to always include this constant in calculations involving probability distributions.

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